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Q. The mass of $112 \, cm^3$ of $NH_3$ gas at $STP$ is

KCETKCET 2013Some Basic Concepts of Chemistry

Solution:

$1\, mol$ of $NH _{3}=17\, g =22400 \,cm ^{3} $ at STP

i.e., $22400\, cm ^{3}$ of $NH _{3}$ at STP have mass $=17 \,g$

$\therefore 112 \,cm ^{3}$ of $NH _{3}$ at STP will have mass

$=\frac{17}{22400} \times 112=0.085\, g$