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  4. The mass (in grams) of glucose that should be dissolved in 100 g of water in order to produce same lowering of vapour pressure as is produced by dissolving 1 g of urea (molecular mass = 60) in 50 g of water is

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Q. The mass (in grams) of glucose that should be dissolved in 100 g of water in order to produce same lowering of vapour pressure as is produced by dissolving 1 g of urea (molecular mass = 60) in 50 g of water is

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Solution:

$\frac{\Delta P}{P_{0}}=X_{B}$

$\approx \frac{n_{B}}{n_{A}}=\frac{w_{B} \times m_{A}}{m_{B} \times w_{A}}$

$\left(\frac{w_{B} \times m_{A}}{m_{B} \times w_{A}}\right)_{g l u c o s e}=\left(\frac{w_{B} \times m_{A}}{m_{B} \times w_{A}}\right)_{u r e a}$

$\frac{w_{B} \times 18}{180 \times 100}=\frac{1 \times 18}{60 \times 50}$

$w_{B}=6$ g.