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  4. The mass defect of 24 H is 0.03 u. The binding energy per nucleon of helium (in M e V ) is

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Q. The mass defect of ${ }_2^4 H$ is $0.03 u$. The binding energy per nucleon of helium (in $M e V$ ) is

KCETKCET 2017Nuclei

Solution:

Mass defect of ${ }_{2}^{4} He =0.03 \,u$
Mass number $=4$
Binding energy $=0.03 \times 931=27.93$
Per nucleon binding energy $=\frac{27.93}{4}$
$=6.9825$