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Q. The marks obtained by $9$ students in a chemistry test are $50,69,20,33,53,39,40,65$ and $59$ . If the mean deviation about the median of this data is $\lambda $ , then the value of $\frac{9 \lambda }{10}$ is equal to

NTA AbhyasNTA Abhyas 2020Statistics

Solution:

$20,33,39,40,50,53,59,65,69$
Median, $M$ $=\left(\frac{9 + 1}{2}\right)^{t h}$ observation $=5^{t h}$ observation $=50$
The absolute values of respective deviations from the median is
$30,17,11,10,0,3,9,15,19$
$\therefore \displaystyle \sum _{i = 1}^{9} \left|x_{i} - M\right|=114$
Mean deviation about $M=\frac{1}{9}\displaystyle \sum _{i = 1}^{9}\left|x_{i} - M\right|=\frac{1}{9}\times 114$
i.e $\lambda =\frac{114}{9}\Rightarrow \frac{9 \lambda }{10}=11.4$