Question

The major product $(P)$ formed in the below reaction is
$H - C \equiv C - CH _{2}- CH = CH _{2} \ce{ ->[{Br_2 (1 mol)}][{CCl_4,253 K}] }P$

• A. $H - C \equiv C - CH _{2}- CH ( Br )- CH _{2}( Br )$
• B. $CH ( Br )_{2}- C ( Br )_{2}- CH _{2}- CH = CH _{2}$
• C. $CH _{2}( Br )- CH ( Br )- CH _{2}- CH = CH _{2}$
• D. $CH _{2}= CH ( Br )- CH ( Br )- CH = CH _{2}$

Answer 1

Answer: (A)

Treatment of alkene with $Br _{2}$ in $CCl _{4}$ solvent gives vicinal dibromides. Bromine added to opposite faces of the double bond (anti addition).

$CH \equiv C - CH _{2}- CH = CH _{2}$