Question

The major product formed in the following reaction is :
$CH _{3} CH = CHCH \left( CH _{3}\right)_{2} \stackrel{ HBr }{\longrightarrow }$

• A. $CH _{3} CH _{2} CH _{2} C ( Br )\left( CH _{3}\right)_{2}$
• B. $\operatorname{Br}\left( CH _{2}\right)_{3} CH \left( CH _{3}\right)_{2}$
• C. $CH _{3} CH _{2} CH ( Br ) CH \left( CH _{3}\right)_{2}$
• D. $CH _{3} CH ( Br ) CH _{2} CH \left( CH _{3}\right)_{2}$

Answer 1

Answer: (C)

Addition of HBr according to M.R.