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Q. The main scale of a vernier caliper reads $10mm$ in $10$ divisions. $10$ divisions of vernier scale coincide with $9$ divisions of the main scale. When the two jaws of the calipers touch each other, the fifth division of the vernier coincides with a main scale division and the zero of the vernier is to the right of zero of the main scale. When a cylinder is tightly placed between the two jaws, the zero of vernier scale lies slightly to the left of $3.2cm$ and the fourth vernier division coincides with the main scale division. The diameter of the cylinder is,

NTA AbhyasNTA Abhyas 2022

Solution:

$LC=\frac{1}{10}mm=0.01cm$
and $e=VSD\times LC=0.05cm$
Therefore,
$TSR=MSR+\left(\right.VSD\times LC\left.\right)-e$
$\Rightarrow TSR=3.1+\left(\right.4\times 0.01\left.\right)-0.05$
$\Rightarrow TSR=3.14-0.05=3.09cm$