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Q. The main product of the reaction would be 2-butene + chloroform $ \,\xrightarrow{\text{NaOH}} $ ?

Jharkhand CECEJharkhand CECE 2014

Solution:

$ C{{H}_{3}}CH=CH-C{{H}_{3}}+CHC{{l}_{3}}\xrightarrow{{}} $ $ C{{H}_{3}}-\overset{CC{{l}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}-C{{H}_{3}}\xrightarrow[\text{hydrol}]{\text{NaOH}} $ $ C{{H}_{3}}-\overset{C(OH)3}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}-C{{H}_{3}}\xrightarrow[{}]{-{{H}_{2}}O} $ $ \underset{2-\text{methyl}\,\text{butanoic}\,\text{acid}}{\mathop{C{{H}_{3}}-\overset{COOH}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}C{{H}_{3}}}}\, $