1. Tardigrade
  2. Question
  3. Physics
  4. The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians) :

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Q. The magnitude of torque on a particle of mass $1\,kg$ is $2.5\, Nm$ about the origin. If the force acting on it is $1\, N$, and the distance of the particle from the origin is $5\,m$, the angle between the force and the position vector is (in radians) :

JEE MainJEE Main 2019System of Particles and Rotational Motion

Solution:

$2.5 = 1 \times 5 \sin \theta$
$\sin \theta = 0.5 = \frac{1}{2}$
$\theta = \frac{\pi}{6}$