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Mathematics
The magnitude of the moment of a force -2 hati+6 hatj-8 hatk acting at the point -2 hati- hatj+3 hatk about the point hati+2 hatj- hatk is:
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Q. The magnitude of the moment of a force $ -2\hat{i}+6\hat{j}-8\hat{k} $ acting at the point $ -2\hat{i}-\hat{j}+3\hat{k} $ about the point $ \hat{i}+2\hat{j}-\hat{k} $ is:
KEAM
KEAM 2000
A
$ \sqrt{211} $
B
$ 40 $
C
$ \sqrt{54} $
D
$ 2\sqrt{54} $
E
$ 72 $
Solution:
Force $ =-2\hat{i}+6\hat{j}-8\hat{k} $ Let $ P(-2,-1,3) $ and $ \text{O}(1,2,-1) $ Then $ \overrightarrow{r}=\overset{\to }{\mathop{OP}}\,=-3,-3,4 $ $ \therefore $ Moment of F about $ O $ is $ \overrightarrow{r}\times \overrightarrow{F}=\left| \begin{matrix} {\hat{i}} & {\hat{j}} & {\hat{k}} \\ -3 & -3 & 4 \\ -2 & 6 & -8 \\ \end{matrix} \right| $ $ =\hat{i}(0)-\hat{j}(32)+\hat{k}(-24) $ $ \therefore $ Magnitude $ =\sqrt{{{32}^{2}}+{{24}^{2}}} $ $ =40 $