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  4. The magnitude of electric field required to just balance in air a 2× 10- 4kg liquid drop carrying a charge of 10× 10- 2 textμC is,

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Q. The magnitude of electric field required to just balance in air a $2\times 10^{- 4}kg$ liquid drop carrying a charge of $10\times 10^{- 2}\text{μC}$ is,

NTA AbhyasNTA Abhyas 2020

Solution:

$qE=mg$
$E=\frac{mg}{q}=\frac{2 \times 10^{- 4} \times 10}{10 \times 10^{- 2} \times 10^{- 6}}=2\times 10^{4}NC^{- 1}$