Question

The magnitude and direction of the current in the circuit shown will be

• A. $7/3$ A from a to b through $e$
• B. $7/3$ A from b to a through $e$
• C. $1A$ from b to a through $e$
• D. $1A$ from a to b through $e$

Answer 1

Answer: (D)

Since $E_1 (10 \,V) > E_2 (4V)$
So, current in the circuit will be clockwise,

Applying Kirchhoff’s voltage law
$-1 × i - 10 - 4 × -2 × i -3i = 0$
$= 1A$ (a to b via e)
Current $I=\frac{V}{R}=\frac{10-4}{6}=1\,A$