Question

The magnitude and direction of the current in the circuit shown will be

• A. $\frac{7}{3} A$ from $a$ to $b$ through $e$
• B. $\frac{7}{3} A$ from $b$ to $a$ through $e$
• C. $1 A$ from $b$ to $a$ through $e$
• D. $1 A$ from $a$ to $b$ through $e$

Answer 1

Answer: (D)

Since $E_{1}(10 V ) > E_{2}(4 V )$
So current in the circuit will be clockwise.

Applying Kirchhoff's voltage law,
$-1 \times i+10-4-2 \times i-3 i=0 $
$\Rightarrow i=1 A (a$ to $b$ via $e)$
$\therefore $ Current $=\frac{V}{R}=\frac{10-4}{6}=1.0$ ampere