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Q. The magnetic moment (spin only) of $[NiCl_{4}]^{2-}$ is

Coordination Compounds

Solution:

$[NiCl_{4}]^{2-}$: oxidation number of Ni, $x - 4 - -2$
$\therefore x = +2, Ni_{(28)} [Ar] 3d^{8}, 4s^{2}$
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$sp^{3}$ hybrid orbitals, tetrahedralSince, $Cl^{-}$ is a weak ligand, thus unpaired electrons are not paired. Lone pairs from $4 \,Cl^{-}$ are accommodated in four $sp^{3}$ hybrid orbitals.
n = unpaired electron = 2, paramagnetic Magnetic moment (spin only)
$=\sqrt{n\left(n+2\right)} BM =\sqrt{8}=2.828 BM$