Magnetic moment of $Zn ^{2+} \mu_{\text {effective }}$ $=\sqrt{n(n+2)} BM$
where, $n=$ Number of unpaired electrons
${ }_{30} Zn =1 s^{2}, 2 s ^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{10}, 4 s^{2}$
$Zn ^{2+}=1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{10}$
So, magnetic moment of $Zn ^{2+}=$ zero