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Q.
The magnetic moment of a bar magnet is $3.6 \times10^{-3}\,A.m^2$ .Its pole strength is 120 milli amp. m. Its magnetic length is
Moving Charges and Magnetism
Solution:
For a bar magnet, the magnetic moment is
$M=polestrength\times magneticlength$
So the magnetic length will be
$l_{mag}=\frac{M}{m}$
$\Rightarrow l_{mag}=\frac{3.6 \times 10^{- 3}}{120 \times 10^{- 3}}=3\times 10^{- 2} \, m=3 \, cm$