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Q.
The magnetic moment associated with a circular coil of $35$ turns and radius $25 \,cm$, if it carries a current of $11 \,A$ is
Moving Charges and Magnetism
Solution:
Given $N = 35$,
$r = 25\, cm$
$=25\times10^{-2}\,m$,
$I=11\,A $
Then magnetic moment associated with this circular coil
$M=NIA=NI\pi r^{2}=35\times11\times3.14\times\left(25\times10^{-2}\right)^{2}$
$=75.56\,A \,m^{2}$