Question

The magnetic force acting on charged particle of charge $2 \mu C$ in magnetic field of $2 T$ acting in $y$ - direction, when the particle velocity is
$\left(2\hat{i}+3\hat{j}\right)\times10^{6}\,ms^{-1}$ is

• A. 8 N in z-direction
• B. 8 N in y-direction
• C. 4 N in y-direction
• D. 4 N in z-direction

Answer 1

Answer: (A)

$\overrightarrow{F} = q\left(\overrightarrow{V}\times\overrightarrow{B}\right)$
$= 2\times10^{-6}\left[\left(2\hat{i}+3\hat{j}\right)\times10^{6}\times2\hat{j}\right]$
$= 2 \times 4\hat{k} = 8$ N in Z-direction.