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Q. The magnetic field due to a straight conductor of uniform cross‐section of radius a and carrying a steady current is represented by

AIIMSAIIMS 2004Moving Charges and Magnetism

Solution:

The magnetic field at a point outside the straight conductor is given by
$B=\frac{\mu_{0} i}{2 \pi r}$
It means $B \propto \frac{1}{r}$
(if $r>a$ )
The magnetic field at a point inside the conductor is
$B=\frac{\mu_{0} i \times r}{2 \pi a^{2}}$
or $B \propto r$ (if $r < a)$
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