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Q. The magnetic field at the centre of semi-circular wire carrying current $ i $ is

Rajasthan PMTRajasthan PMT 2003Moving Charges and Magnetism

Solution:

Magnetic field at centre of a circular coil,
$B=\frac{\mu_{0} N i}{2 r}$
Here $N=\frac{1}{2}$
$\therefore B =\frac{\mu_{0}\left(\frac{1}{2}\right) i}{2 r}$
$=\frac{\mu_{0} i}{4 r}$