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Q. The lowest Bohr orbit in hydrogen atom has

J & K CETJ & K CET 2016Atoms

Solution:

The energy of $n^{th}$ Bohr orbit in hydrogen atom is
$E_{n}=-\frac{13.6}{n^{2}} eV $
For lowest orbit, $n=1$
$\therefore E_{1}=-13.6\,eV$
For highest orbit, $n=\infty$
$\therefore E_{n}=0\,eV$
Thus, the lowest Bohr orbit in hydrogen atom has the least energy