Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The lowering of vapour pressure of the solvent takes place on dissolving a non-volatile solute because

Solutions

Solution:

Vapour pressure does not depend upon surface area of a volatile liquid $\frac{p}{p^\circ}= x_{solvent}$ In case of a solution rsoivem $< 1. \, \therefore \,p < p^{\circ}$