Q.
The logic gate represented in following figure is
Solution:
Truth table of this gate
A
B
Y'
Y
0
0
1
0
1
0
0
1
0
1
0
1
1
1
0
1
$Y' = \overline{A+B} = \bar{A}\times\bar{B}$
and $Y=\bar{Y}'=\overline{\bar{A}\times\bar{B}}=\bar{\bar{A}} +\bar{\bar{B}}=A+B$
This is the boolean expression for the OR gate.
| A | B | Y' | Y |
|---|---|---|---|
| 0 | 0 | 1 | 0 |
| 1 | 0 | 0 | 1 |
| 0 | 1 | 0 | 1 |
| 1 | 1 | 0 | 1 |
