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Q. The logarithm of the equilibrium constant of the cell reaction corresponding to the cell $X(s)\left| X^{2+}(a q) \| Y^{+}(a q)\right| Y(s)$ with standard cell potential, $E_{\text {cell }}^{\circ}=1.2\, V$ is given by

AMUAMU 2010Electrochemistry

Solution:

image
Thus, $n=2$
$E_{\text {cell }}^{\circ} =\frac{0.0591}{n} \log K_{c}$
$1.2 =\frac{0.0591}{2} \log K_{c}$
$\log K_{c} =\frac{1.2 \times 2}{0.0591}$
$=40.6$