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Q.
The locus represented by $xy + yz = 0$ is
Three Dimensional Geometry
Solution:
$xy + yz = 0$
$y(x + z) = 0$
$\Rightarrow y = 0$ and $(x + z) = 0$
$\Rightarrow y = 0$ is a equation of $xz$-plane.
$\Rightarrow x + z$ is also an equation of plane.
$d$.$r'$.$s$ of normal to the plane $y = 0$ is $(0, 1, 0)$ and $d$.$r'$.$s$ of normal to the plane $x + z = 0$ is $(1, 0, 1)$
Now, $a_1a_2 + b_1b_2 + c_1c_2 = 0 \times 1 + 1 \times 0 + 0 \times 1 = 0$
Hence, both planes are perpendicular.