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Q.
The linear momentum of a $6\, MeV$ photon is
Dual Nature of Radiation and Matter
Solution:
Energy of a photon, $E=6 \,MeV =6 \times 10^{6} \,eV$
Linear momentum of the photon
$p=\frac{E}{c}$
$P=\frac{6 \times 10^{6} eV }{3 \times 10^{8} \,ms ^{-1}}$
$=2 \times 10^{-2} \,eV\,s m ^{-1}$
$=0.02\, eVs\, m ^{-1}$