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Tardigrade
Question
Chemistry
The linear molecule is
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Q. The linear molecule is
MGIMS Wardha
MGIMS Wardha 2010
A
$ C{{H}_{4}} $
B
$ {{C}_{2}}{{H}_{2}} $
C
$ N{{H}_{3}} $
D
$ {{H}_{2}}O $
Solution:
Molecule
Hybridisation
Geometry
$ C{{H}_{4}} $
$ s{{p}^{3}} $
Tetrahedral
$ {{C}_{2}}{{H}_{2}} $
$ sp $
Linear
$ N{{H}_{3}} $
$ s{{p}^{3}} $
Pyramidal (due to $ 1lp $ )
$ {{H}_{2}}O $
$ s{{p}^{3}} $
V-shaped (due to $ 2lp $ )