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Q. The line which is parallel to X-axis and crosses the curve $y = \sqrt{x}$ at an angle of $45^{\circ}$, is

BITSATBITSAT 2015

Solution:

Let the line parallel to $x$ axis be $y=k$.So,the point of intersection of the line and the curve will be $\left( k ^{2}, k \right)$. The slope of the curve at any point $( x , y )$ is $\frac{\partial y }{\partial x }=$ $\frac{1}{2 \sqrt{x}}=\frac{1}{2 k}=1$
Hence $k=1 / 2$