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Q. The line passing through the extremity $A$ of the major axis and extremity $B$ of the minor axis of the ellipse $x^{2}+9 y^{2}=9$ meets its auxiliary circle at the point $M$. Then the area of the triangle with vertices at $A, M$ and the origin $O$ is

JEE AdvancedJEE Advanced 2009

Solution:

Equation of line AM is $x+3 y-3=0$
Perpendicular distance of line from origin $=\frac{3}{\sqrt{10}}$
Length of $AM =2 \sqrt{9-\frac{9}{10}}=2 \times \frac{9}{\sqrt{10}}$
$\Rightarrow $ Area $=\frac{1}{2} \times 2 \times \frac{9}{\sqrt{10}} \times \frac{3}{\sqrt{10}}=\frac{27}{10}$ sq. units.