Question

The limiting line in Balmer series will have a frequency of

• A. $32.29 \times 10^{15} \,s ^{-1}$
• B. $3.65 \times 10^{14}\, s ^{-1}$
• C. $-8.22 \times 10^{14} \,s ^{-1}$
• D. $8.22 \times 10^{14} \,s ^{-1}$

Answer 1

Answer: (C)

The limiting line of Balmer series refers to the transition from $\infty$ to 2 nd orbit.
$v =3.29 \times 10^{15}\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right) s^{-1}\left(n_1=2, n=\infty\right)$
$ =3.29 \times 10^{15} \times \frac{1}{4}=8.22 \times 10^{14} s ^{-1}$