1. Tardigrade
  2. Question
  3. Physics
  4. The length of the resistance wire is increased by 10 %. What is the corresponding change in the resistance of wire?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The length of the resistance wire is increased by $10 \%$. What is the corresponding change in the resistance of wire?

Current Electricity

Solution:

$\frac{R_{1}}{R_{2}}=\left(\frac{l_{1}}{l_{2}}\right)^{2}$,
if $l_{1}=100$, then $l_{2}=110$
$\Rightarrow \frac{R_{1}}{R_{2}}=\left(\frac{100}{110}\right)^{2}$
$\Rightarrow R_{2}=1.21 R_{1}$
$\%$ change $=\frac{R_{2}-R_{1}}{R_{1}} \times 100=21 \%$