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Q. The length of the Latus rectum of the parabola $x=a y^{2}+b y+c$ is

KEAMKEAM 2019

Solution:

Given, $x=a y^{2}+b y+c$
$\Rightarrow \left(y+\frac{b}{2 a}\right)^{2}=\frac{1}{a}\left(x+\frac{b^{2}-4 a c}{4 a}\right)$
Latus rectum $=\frac{1}{a}$