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Q.
The length of one turn of the helix in B-form DNA is approximately
Haryana PMTHaryana PMT 2010
Solution:
B-form of DNA shows right-handed coiling which contains $10$ base pairs in each turn. On complete turn, DNA occupies $34$ A distance.
So in nm, it will $3.4 \,nm $ because or.
$1 n m=10^{-9} \,m$
$1\,\mathring{A}=10^{10}\, m$
So $34\,\mathring{A} =34\, x\, 10^{10} \,m$
$=3.4 \,nm$