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Q.
The length of a magnetised steel wire is $l$ and the magnetic moment is $m$. It is bent into the shape of $L$ with two sides equal. The magnetic moment now will be
Magnetism and Matter
Solution:
If $q_{m}$ is strength of each pole, then $m=q_{m} \times l$. When the wire is bent into $L$ shape effective distance between the poles
$=\sqrt{(l / 2)^{2}+(l / 2)^{2}}=l / \sqrt{2}$
$\therefore m^{\prime} =q_{m} \times \frac{l}{\sqrt{2}}=\frac{m}{\sqrt{2}}$ $(m \text { will remain unchanged) }$