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Physics
The length and breadth of a rectangle are (5.5 ± 0.1) cm and (2.5 ± 0.1) cm. Calculate area of the rectangle with error limit.
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Q. The length and breadth of a rectangle are $(5.5 \pm 0.1) cm$ and $(2.5 \pm 0.1) cm$. Calculate area of the rectangle with error limit.
A
$(13 \pm 0.8) cm ^{2}$
12%
B
$(14 \pm 0.8) cm ^{2}$
59%
C
$(13 \pm 0.6) cm ^{2}$
18%
D
$(14 \pm 0.6) cm ^{2}$
12%
Solution:
$A =$ L.b. $=(5.5 \times 2.5)=13.75\, cm ^{2} \approx 14 \,cm ^{2}$
$\frac{\Delta A }{ A }=\frac{\Delta \ell}{\ell}+\frac{\Delta b }{ b }=\frac{0.1}{5.5}+\frac{0.1}{2.5}$
$\Delta A =(5.5 \times 2.5) \frac{(0.1)(2.5+5.5)}{(5.5 \times 2.5)}$
$ \Rightarrow 0.8 \,cm ^{2}$