Q.
The least count of stop watch is $\frac{1}{5}$ second.
The time of $20$ oscillations of pendulum is measured to be $25$ seconds. Then percentage error in the measurement of time will be
NTA AbhyasNTA Abhyas 2022
Solution:
As we know that the percentage error is defined as when we multiply the relative error with hundred then it becomes percentage error.
So, we can write the percentage error as,
$\frac{\Delta t}{t}\times 100=\frac{0 . 2}{25}\times 100=0.8\%$
that's why correct option is $\left(A\right)$
So, we can write the percentage error as,
$\frac{\Delta t}{t}\times 100=\frac{0 . 2}{25}\times 100=0.8\%$
that's why correct option is $\left(A\right)$