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  4. The least count of a stop watch is (1/5) second. The time of 20 oscillations of a pendulum is measured to be 25 seconds. The maximum percentage error in the measurement of time will be

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Q. The least count of a stop watch is $\frac{1}{5}$ second. The time of $20$ oscillations of a pendulum is measured to be $25$ seconds. The maximum percentage error in the measurement of time will be

Physical World, Units and Measurements

Solution:

Least count $=\Delta T=\frac{1}{5} s =0.2\, s$
$T=25\, s$
Percentage error $=\frac{\Delta T}{T} \times 100 \%$
$=\frac{0.2}{25} \times 100 \%=0.8 \%$