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  4. The latent heat of vaporisation of water is 9700 cal/mole and if the b.p. is 100°C, ebullioscopic constant of water is

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Q. The latent heat of vaporisation of water is $9700\, cal/mole$ and if the b.p. is $100^{\circ}C$, ebullioscopic constant of water is

Solutions

Solution:

$K_{b}=\frac{M_{1} RT_{0}^{2}}{1000\,\Delta H_{V}}$
$=\frac{18\times1.987\times\left(373\right)^{2}}{1000\times9700}$
$=0.513^{\circ}C$