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Q.
The largest number of molecules is in
IIT JEEIIT JEE 1979Some Basic Concepts of Chemistry
Solution:
Number of molecules present in $36\, g$ of water $=\frac{36}{18} \times N_{A}=2 N_{A}$
Number of molecules present in $28\, g$ of $CO =\frac{28}{28} \times N_{A}=N_{A}$
Number of molecules present in $46\, g$ of $C _{2} H _{5} OH =\frac{46}{46} \times N_{A}=N_{A}$
Here, $N_{A}$ is Avogadro's number. Hence, $36 \,g$ of water contain the largest $\left(2 N_{A}\right)$ number of molecules.