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Q.
The largest distance of the image from a convex mirror of focal length $10\, cm$ can be
Ray Optics and Optical Instruments
Solution:
For a real object, in case' of a convex mirror, the images formed between the pole and focus.
$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$
$\Rightarrow \frac{1}{v}=\frac{1}{f}-\frac{1}{u}$
$\frac{1}{v}=\frac{u-f}{u f}$
$\Rightarrow v=\frac{u f}{u-f}=\frac{f}{1-\left(\frac{f}{u}\right)}$
As $u$ is -ve for a real object, $f$ is +ve for convex mirror,
$v=\frac{f}{1+\left(\frac{f}{u}\right)}\Rightarrow |v|<|f| \cdot s$