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  4. The kinetic energy of the photoelectrons increases by 0.52 eV when the wavelength of incident light is changed from 500 nm to another wavelength which is approximately

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Q. The kinetic energy of the photoelectrons increases by $0.52 \,eV$ when the wavelength of incident light is changed from $500\, nm$ to another wavelength which is approximately

KCETKCET 2022Dual Nature of Radiation and Matter

Solution:

$KE _{1}- KE _{2}=\frac{ hc }{\lambda_{1}}-\frac{ hc }{\lambda_{2}}$
$\Delta KE = hc \left[\frac{1}{\lambda_{1}}-\frac{1}{\lambda_{2}}\right]$