Question

The kinetic energy of one molecule of a gas at normal temperature and pressure will be ($k=8.31\,J$ mole$ K$):

• A. $ 1.7\times 10^{3} J$
• B. $ 10.2\times 10^{3} J$
• C. $ 3.4\times 10^{3} J$
• D. $ 6.8\times 10^{3} J$

Answer 1

Answer: (C)

According to kinetic theory, K.E. of $1\,g$-mole of an ideal gas, $E=\frac{3}{2} R T$
Hence, K.E. at normal temperature $0^{\circ} C$
$=273\, K$
or $E =\frac{3}{2} \times 8.31 \times 273=3.4 \times 10^{3} J$