1. Tardigrade
  2. Question
  3. Physics
  4. The kinetic energy of an electron is 5 eV. Calculate the de-Broglie wavelength associated with it ( h=6.6 × 10-34 Js, .me=9.1 × 10-31 kg )

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The kinetic energy of an electron is $5\, eV$. Calculate the de-Broglie wavelength associated with it ( $h=6.6 \times 10^{-34} Js$, $\left.m_{e}=9.1 \times 10^{-31} kg \right)$

JIPMERJIPMER 2004Dual Nature of Radiation and Matter

Solution:

Wavelength associated with an electron
$\lambda =\frac{h}{\sqrt{2 m E}}$
$=\frac{6.6 \times 10^{-34}}{\sqrt{2 \times 9.1 \times 10^{-31} \times 5 \times 1.6 \times 10^{19}}}$
$=5.47 \times 10^{-10} m =5.47\,\mathring{A}$