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Q. The $K_{sp}$ of $Mg ( OH )_{2}$ is $1 \times 10^{-12} ; 0.01\, M \,MgCl _{2}$ will precipitate at limiting $pH$ of _____.

Equilibrium

Solution:

$\left[ Mg ^{2+}\right]=0.01 \,M , K _{s p}=\left[ Mg ^{2+}\right][ OH ]^{2}$

$1 \times 10^{-12}=0.01 \times[ OH ]^{2},[ OH ]=10^{-5} M$

$pOH =-\log 10^{-5}=5, pH =14-5=9$