Question

The jaws of the Vernier callipers shown in figure are in contact with each other. The zero error of this Vernier calipers is $\frac{x}{10}mm$ . Find $x$ .

Answer 1

The least count of given Vernier Calipers is
$LC=MSD-VSD=1-\left(9 / 10\right)=0.1\,mm$
The main scale reading is $MSR_{0}=0\,mm$ and the Vernier scale reading is $VSR_{0}=3.$ Thus,
Zero Error $=MSR_{0}+VSR_{0}\times LC$
$=0+3\times 0.1=0.3\,mm$