Q.
The ionization of a weak acid in aqueous solution can be represented as:
Dissociation constant of acid $= K _{ a }=\frac{\left[ H ^{+}\right]\left[ A ^{-}\right]}{[ HA ]}$
$=\frac{( c \alpha)( c \alpha)}{ c (1-\alpha)} $
$Ka =\frac{ c \alpha^{2}}{1-\alpha}$
Two solutions are said to be isohydric when the amount of dissociation of each solute is unchanged by mixing the solutions. Let two weak acids $HA _{1}$ and $HA _{2}$ are taken of concentration $c _{1}$ and $c _{2}$ respectively and their degrees of dissociation are $\alpha_{1}$ and $\alpha_{2}$ (before mixing) respectively. After mixing the two acids, let their degrees of dissociation remain unchanged but their concentration change.
Solutions of $HA _{1}$ and $HA _{2}$ will be isohydric when
Equilibrium
Solution: