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  4. The ionization enthalpy of He+ ion is 19.60 ×10-18 J atom-1. The ionization enthalpy of Li2+ ion will be

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Q. The ionization enthalpy of $He^{+} ion is 19.60 \times10^{-18} J atom^{-1}.$ The ionization enthalpy of $Li^{2+}$ ion will be

Structure of Atom

Solution:

Ionisation enthalpy $\propto Z^{2} \left(Z=Atomic\, numder\right)$
Ionisation enthalpy of $Li^{2+}=I.E. of He^{+}\times\left(\frac{3^{2}}{2^{2}}\right) $
$I.E. of \, Li^{2+}=19.6\times10^{-18}\times\frac{9}{4}=44.1\times10^{-18} J \, atom^{-1}$