1. Tardigrade
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  3. Chemistry
  4. The ionization constant of phenol is 1.0 × 10-10 . Thus, pH of a mixture of 0.05 M phenolate ion and 0.01 M phenol solution, is

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Q. The ionization constant of phenol is $1.0 \times 10^{-10} .$ Thus, $pH$ of a mixture of $0.05 \,M$ phenolate ion and $0.01 \,M$ phenol solution, is

Equilibrium

Solution:

image

$K_{a}=\frac{[B]\left[ H _{3} O ^{+}\right]}{0.01}$

$1. 0 \times 10^{-10}=\frac{0.05 \times\left[ H _{3} O ^{+}\right]}{0.01}$

$ \therefore \left[ H _{3} O ^{+}\right] =\frac{1.0 \times 10^{-10}}{5}=2 \times 10^{-11} $
$\therefore pH =-\log \left[ H _{3} O ^{+}\right]=-\log \left(2 \times 10^{-11}\right) $

$ pH =10.7$