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Q. The ionisation constant of ammonium hydroxide is $ 1.77\times {{10}^{-5}} $ at 298 K. Hydrolysis constant of ammonium chloride is

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Solution:

$ {{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{b}}}=\frac{1\times {{10}^{-14}}}{1.77\times {{10}^{-5}}}=5.65\times {{10}^{-10}} $