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Chemistry
The ionic radii of Rb+ and I- are 1.46 and 2.16 mathringA. The most probable type of structure exhibited by it is
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Q. The ionic radii of $Rb^+$ and $I^-$ are $1.46$ and $2.16 \, \mathring{A}$. The most probable type of structure exhibited by it is
The Solid State
A
$CsCl$ type
20%
B
$NaCl$ type
62%
C
$ZnS$ type
7%
D
$CaF_2$ type
11%
Solution:
Radius ratio $\frac{r_{Rb^+}}{r_{I^-}} = \frac{1.46}{2.16} = 0.68$
$\Rightarrow $ Between $0.414$ and $0.732$
Hence rock salt $(NaCl)$ structure.